@Jose and Fliker09: Since we're totally spread all over the world "Team Asia" doesn't fit at all. So I thought that, since we're spread out so extreme we could be "Team Extreme", what do you think? Another good thing about that name that it sounds dangerous and might intimidate our opponents. ;-)

Since w1zrd and KIAaze would like to leave we can change the final teaming this way. We remove the AirFrag team and have the remaining members in the other teams. It would look like this:

Team 1 (Team Extreme, HK/Moldova/US):

reptiler
Fliker09
Jose

Team 2 (US)

Plouj
Atma
Johpunk (Venezela)
Spyro_boy

Team 3 (EU):

Skateinmars
efus
DeathZone
vostorga

Plus existing teams:

Valherus
BRUTAL
EGUSS
Thunder_PT's team
FM|

That is total 8 teams meaning we have 2 groups of 4 teams. Team 2 and 3 do have an extra player, but that is backup (which three play in which match is up to them).

So random groups could look like this:

Group 1:

Thunder_PT's team
BRUTAL
Team 2 (US)
FM|
T.S (edited)

Group 2:

EGUSS
Team 1 (Team Extreme, HK/Moldova/US)
Team 3 (EU)
Valherus

My apologies. I overlooked the request of another team to be added before we formed groups and now got to the email about it right after I formed the above teams and groups.

I'm adding T.S OpenArena CTF team to the first group. That is the only change. This does mean that the teams in first group will play more qualification matches than the second group, but this is both an advantage and a disadvantage because while it means more competition it also means more chances to win qualifying points. So the balance is achieved.

If anyone has any objections to it they will be noted.

I propose that the second group have a match added to their line-up. It would be random. It would mean that each team in that group would play someone twice.

******

EDIT (a few minutes later):

The end result would be that absolutely everyone plays 4 matches. This would mean that there would be 10 matches in the first group of 5 (5 times 4 matches, divided by 2) and 8 matches in the second group (4 times 4 matches, divided by 2).

Otherwise those unlucky to draw into the second group could only amass 4 points times 3 games = 12 points, instead of the 16 points of the first group. It's true. It isn't a huge deal to miss out on 4 points when you consider all the points that can be gained throughout all the tournaments (and points are only used for the Universal Winner calculation), but if there is no harm otherwise, I vote to have the second group keep up with the first group in terms of total points achievable/ total games played.

[I know I haven't replied directly to the last email you sent me. I was avoiding discussing the issue again without first taking a break. I expect the reply not to be very long, but I wanted to squeeze in there some words comparing average vs total points. I want to do that while keeping it short and sweet. Yes, that is challenging!

My overall view, as stated already, once I realized that total points were summed over all matches from all tournaments, is that total points works because everyone has roughly the same opportunity to accumulate the same number of total points. With this being the case, I favor total points over average because total points implies the winner did decent enough and participated a lot (or participated decently but did awesomely). Highest average would work, but we would have to get serious about enforcing minumum "at bats", ie, adjustments. Since this is voodoo science to be avoided if possible, I don't see why we wouldn't use the quite fair total points system [Re-emphasis: totals work because anyone can take part in all tournaments and you want to reward that with a "universal" winner title, I think. Average actually encourages limited and calculated participation. It's fine, but it isn't "universal" to the same extent. ]]

If everyone plays everyone else twice in the second group each player in it will get to play 6 matches while the first plays 4. Again it's not equal. Unless you mean picking only one pair to play each other twice?

OK. I'm in the second group (Team 1). I get 3 matches because there are 3 other teams in my group. You can count and verify I have 3 matches. Each of the other 3 teams also has 3 matches. The total number of matches then for our group is 4*3/2=6 which can be verified by looking at the page and counting.

Now, imagine taking a 6-sided die (a cube) and rolling it. Some number shows up. You go back to the section showing the group 2 matchups and count from the top until you get to that number. That match pair plays again. Then we take the 2 players that were not involved in that match pairing and they play each other. Thus we get 8 total matches and each player adds on an extra match to finish out with 4 a piece.

More specifically, I roll a three. I go here http://www.freedomware-gamefest.com/openarena-ctf-tournament and find that the third match listed for group 2 is EGUSS - Valherus. This will be one of the two extra matches, and the other would be Team 1 vs Team 3 as these are the two teams not included in the first extra match.

So the end result (had I rolled a 3 and followed this procedure) would be:
EGUSS - Team 1
EGUSS - Team 3
EGUSS - Valherus
Team 1 - Team 3
Team 1 - Valherus
Team 3 - Valherus
EGUSS - Valherus
Team 1 - Team 3
[Note the last 2 entries which were added to the 6 entries listed on the page]

In my case this means Team 1 would play EGUSS and Valherus once and Team 3 twice as can be verified by this last list.

Of course, feel free to roll a number besides 3 if you'd like.

The other important point here is that least until the first match, I can dream of accumulating 16 points.

Proposed Nexuiz CTF teams, if it makes any sense to even hold a Nexuiz CTF tourney with only 5 teams and hence only 1 group.The qualifications are merely a warm up in such a case.. only one can be disqualified to have anyhow meaningful tournament..

Here we go:

Team 1:

- Plouj
- johpunk
- Spyro_boy

Team 2:

- Jose
- reptiler
- Fliker09
- chandrahas9

Team 3:

- Skateinmars
- efus
- FruitieX
- Diomedes

Team 4:

- Rad Ished
- morfar
- parp
- killgenerals

- Thunder_PT's team

Group 1:

Team 1
Team 2
Team 3
Team 4
Thunder_PT's team

Teams are mostly based on location or otherwise synchronized to OA CTF or random. I don't know the exact location of everyone in Team 4.

People who registered should be frequently checking back and making sure that any of teaming and groupings are ok with them. Otherwise it is presumed fine.

>> if it makes any sense to even hold a Nexuiz CTF tourney with only 5 teams and hence only 1 group.The qualifications are merely a warm up in such a case.. only one can be disqualified to have anyhow meaningful tournament..

@Jose and Fliker09: Since we're totally spread all over the world "Team Asia" doesn't fit at all. So I thought that, since we're spread out so extreme we could be "Team Extreme", what do you think? Another good thing about that name that it sounds dangerous and might intimidate our opponents. ;-)

Since w1zrd and KIAaze would like to leave we can change the final teaming this way. We remove the AirFrag team and have the remaining members in the other teams. It would look like this:

Team 1 (Team Extreme, HK/Moldova/US):

reptiler

Fliker09

Jose

Team 2 (US)

Plouj

Atma

Johpunk (Venezela)

Spyro_boy

Team 3 (EU):

Skateinmars

efus

DeathZone

vostorga

Plus existing teams:

Valherus

BRUTAL

EGUSS

Thunder_PT's team

FM|

That is total 8 teams meaning we have 2 groups of 4 teams. Team 2 and 3 do have an extra player, but that is backup (which three play in which match is up to them).

So random groups could look like this:

Group 1:Thunder_PT's team

BRUTAL

Team 2 (US)

FM|

T.S

(edited)Group 2:EGUSS

Team 1 (Team Extreme, HK/Moldova/US)

Team 3 (EU)

Valherus

Thoughts?

Final groups/teams here: http://www.freedomware-gamefest.com/openarena-ctf-tournament

OA CTF can proceed with the qualifiers.

My apologies. I overlooked the request of another team to be added before we formed groups and now got to the email about it right after I formed the above teams and groups.

I'm adding T.S OpenArena CTF team to the first group. That is the only change. This does mean that the teams in first group will play more qualification matches than the second group, but this is both an advantage and a disadvantage because while it means more competition it also means more chances to win qualifying points. So the balance is achieved.

If anyone has any objections to it they will be noted.

Thanks

I propose that the second group have a match added to their line-up. It would be random. It would mean that each team in that group would play someone twice.

******

EDIT (a few minutes later):

The end result would be that absolutely everyone plays 4 matches. This would mean that there would be 10 matches in the first group of 5 (5 times 4 matches, divided by 2) and 8 matches in the second group (4 times 4 matches, divided by 2).

Otherwise those unlucky to draw into the second group could only amass 4 points times 3 games = 12 points, instead of the 16 points of the first group. It's true. It isn't a huge deal to miss out on 4 points when you consider all the points that can be gained throughout all the tournaments (and points are only used for the Universal Winner calculation), but if there is no harm otherwise, I vote to have the second group keep up with the first group in terms of total points achievable/ total games played.

[I know I haven't replied directly to the last email you sent me. I was avoiding discussing the issue again without first taking a break. I expect the reply not to be very long, but I wanted to squeeze in there some words comparing average vs total points. I want to do that while keeping it short and sweet. Yes, that is challenging!

My overall view, as stated already, once I realized that total points were summed over all matches from all tournaments, is that total points works because everyone has roughly the same opportunity to accumulate the same number of total points. With this being the case, I favor total points over average because total points implies the winner did decent enough and participated a lot (or participated decently but did awesomely). Highest average would work, but we would have to get serious about enforcing minumum "at bats", ie, adjustments. Since this is voodoo science to be avoided if possible, I don't see why we wouldn't use the quite fair total points system [Re-emphasis: totals work because anyone can take part in all tournaments and you want to reward that with a "universal" winner title, I think. Average actually encourages limited and calculated participation. It's fine, but it isn't "universal" to the same extent. ]]

If everyone plays everyone else twice in the second group each player in it will get to play 6 matches while the first plays 4. Again it's not equal. Unless you mean picking only one pair to play each other twice?

>> Unless you mean picking only one pair to play each other twice?

This is probably what I mean, but I'll be more clear just in case.

The match pairings are found here: http://www.freedomware-gamefest.com/openarena-ctf-tournament

OK. I'm in the second group (Team 1). I get 3 matches because there are 3 other teams in my group. You can count and verify I have 3 matches. Each of the other 3 teams also has 3 matches. The total number of matches then for our group is 4*3/2=6 which can be verified by looking at the page and counting.

Now, imagine taking a 6-sided die (a cube) and rolling it. Some number shows up. You go back to the section showing the group 2 matchups and count from the top until you get to that number. That match pair plays again. Then we take the 2 players that were not involved in that match pairing and they play each other. Thus we get 8 total matches and each player adds on an extra match to finish out with 4 a piece.

More specifically, I roll a three. I go here http://www.freedomware-gamefest.com/openarena-ctf-tournament and find that the third match listed for group 2 is EGUSS - Valherus. This will be one of the two extra matches, and the other would be Team 1 vs Team 3 as these are the two teams not included in the first extra match.

So the end result (had I rolled a 3 and followed this procedure) would be:

EGUSS - Team 1

EGUSS - Team 3

EGUSS - Valherus

Team 1 - Team 3

Team 1 - Valherus

Team 3 - Valherus

EGUSS - Valherus

Team 1 - Team 3

[Note the last 2 entries which were added to the 6 entries listed on the page]

In my case this means Team 1 would play EGUSS and Valherus once and Team 3 twice as can be verified by this last list.

Of course, feel free to roll a number besides 3 if you'd like.

The other important point here is that least until the first match, I can dream of accumulating 16 points.

Proposed Nexuiz CTF teams, if it makes any sense to even hold a Nexuiz CTF tourney with only 5 teams and hence only 1 group.The qualifications are merely a warm up in such a case.. only one can be disqualified to have anyhow meaningful tournament..

Here we go:

Team 1:

- Plouj

- johpunk

- Spyro_boy

Team 2:

- Jose

- reptiler

- Fliker09

- chandrahas9

Team 3:

- Skateinmars

- efus

- FruitieX

- Diomedes

Team 4:

- Rad Ished

- morfar

- parp

- killgenerals

- Thunder_PT's team

Group 1:

Team 1

Team 2

Team 3

Team 4

Thunder_PT's team

Teams are mostly based on location or otherwise synchronized to OA CTF or random. I don't know the exact location of everyone in Team 4.

People who registered should be frequently checking back and making sure that any of teaming and groupings are ok with them. Otherwise it is presumed fine.

>> if it makes any sense to even hold a Nexuiz CTF tourney with only 5 teams and hence only 1 group.The qualifications are merely a warm up in such a case.. only one can be disqualified to have anyhow meaningful tournament..

Don't be so pessimistic.

Of course it makes sense.